Cut The Knot!An interactive column using Java applets
by Alex Bogomolny
June 1, 1998
Drawing on the Right Side of the Brain is a drawing-instruction book, first published in 1979. In her book, Betty Edwards, Professor of Arts at California State University, builds on the then novel theory that the two halves of the brain function differently. The left hemisphere is responsible for verbal, abstract, symbolic activities. The right hemisphere serves for synthetic, holistic, intuitive perception and information processing. Under normal circumstances, the left hemisphere is the more active of the two. The book offers a series of exercises designed to subdue the rational, left side of the brain while firing up its right, imaginative side. The book carries the subtitle of A Course in Enhancing Creativity and Artistic Confidence. In the preface to the second edition (1989), the author describes how surprised she was to discover that, in the 10 year period following publication of the book,
Conspicuously absent from this list are school teachers, and math teachers in particular. I do not believe the above passage is the result of a purposeful statistical study and do not intend to draw far-fetched conclusions from it. It just made me ponder whether, holistically speaking, a similar approach may work for math instruction. Drawing is an R-mode (R for right) activity. Now, what can be said about mathematics? Mathematics is verbal, because it's a language, and it is abstract, for in its heart one finds proofs and axiomatizations. It is symbolic, rational, logical, and, nowadays, it is very digital. These are all indications that mathematics is firmly entrenched in the analytic domain of the L-mode (L for left) way of thinking and perception.
On second thought, if the L-mode prevails for most people, and mathematics is an L-mode activity, why is innumeracy so prevalent? After all, the left, analytic hemisphere of the brain is dominant more often than not. So perhaps mathematical thinking is R-modal after all. It is math instruction that has come to depend on the L-mode. If this discrepancy is the source of our widespread innumeracy, perhaps math instruction should exploit more of the R-mode facilities?
I take at the face value the fact that Edwards' book has been used in the circles far removed from the art of or the need for drawing (nursing schools, corporate seminars). When you teach creativity as a stepping stone for drawing, you teach a skill that can be applied elsewhere, even outside the classroom. This leads to a criteria for evaluation of the current math instruction methods. Does anything taught in the math classroom prepare students to face aspects of reality not directly related to math? Students who have taken B. Edwards' course have also learned to see the world differently and to use their mental powers better. Is this true of math instruction? Unfortunately, I think, not. Even more so when math instruction emphasizes "real world problems": most of these problems are dull and have limited utility anyway. It appears possible to learn drawing for drawing's sake and acquire a more universal skill along the way. It should be possible to perform the same feat in math classrooms. I assume math instructors would be proud to be nurturing their students' imagination.
One of the arguments against New Mathematics was that its heavy formalism had little to do with how mathematicians really work. Humanistic Mathematics presents it in a humane way with a human context. One aspect of which is how the real mathematicians do it. No, not every one was born to become a mathematician, but that is beside the point. Future biologists dissect worms and frogs in biology labs, but so do future engineers and future literary agents. Without creativity and imagination mathematics would not be possible. As Edwards' experience demonstrates (see also books by E. de Bono), these skills can be taught. I suspect that good math instruction should foster students' creativity in a deliberate manner and as a part of curriculum.
In B. Edwards' terminology, positive spaces comprise objects drawn intentionally. Negative spaces combine into the set-theoretical complement of the positive spaces. Naturally, both define the same shape. However, concentrating on the positive spaces is liable to activate our object recognition mechanism and reinforce the L-mode. In order to give the R-mode a fighting chance, one of the chapters of the book recommends concentrating on the negative spaces which usually comprise unnamed pieces. Any parallel to mathematics would probably be too farfetched. However, consider the two applets below presenting two related puzzles: Peg Solitaire (on the left) and Reverse Peg Solitaire (on the rIght.) Berlekamp et al quote G.W.Leibniz:
This quote fills my heart with humility as I find it by far more difficult to solve the second puzzle.
In both puzzles, the goal is to reduce a starting configuration to the target one. In the original Solitaire, the target configuration has a single peg in the middle of the board. Following I. Stewart (J. Rec. Math 5, 1972, p. 133), we describe de Bruijn's necessary condition for two configurations to be transformable into each other in a sequence of eligible moves.
Imagine an integer grid overlaid on top of the puzzle with the origin at the center of the board. The pegs are 1 unit apart so that each may be assigned a pair of integer coordinates (x,y). Let a be a number yet to be specified. For a given configuration S of pegs, form the sum A(S) = ax+y, where the sum is taken only for the pegs present in the configuration S. It is easy to verify that A(S) remains invariant under eligible moves if a satisfies two quadratic equations:
Does a number like this exist? (1.1) and (1.2) imply a2 = 1 so that a may only be ±1 neither of which satisfies either (1.1) or (1.2). Never mind, let's bend the rules a little. Let a be an element of the Galois field GF(22) with operations defined by two Cayley tables
In GF(22), (1.1) and (1.2) both become
which is satisfied by both p and q. With this choice of a, A(S) is invariant and so is B(S) = ax-y. For the original position,
For the target position with a single peg the same is true. What other 1 peg positions have the same property? For a 1 peg position, (2) reduces to ax+y = ax-y = 1. Multiplying (1) by a and adding 1 to both sides of the equality gives
(That both p and q are of order 3 also follows from the multiplication table above.) Only five points, (±3,0), (0, ±3), and (0,0) belong to the board and satisfy ax+y = ax-y = 1. All other 1 peg configurations are unreachable.
Alex Bogomolny has started and still maintains a popular Web site Interactive Mathematics Miscellany and Puzzles to which he brought more than 10 years of college instruction and, at least as much, programming experience. He holds M.S. degree in Mathematics from the Moscow State University and Ph.D. in Applied Mathematics from the Hebrew University of Jerusalem. He can be reached at firstname.lastname@example.org
Copyright © 1997 Alexander Bogomolny